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10.75x^2+20x+48.55=800
We move all terms to the left:
10.75x^2+20x+48.55-(800)=0
We add all the numbers together, and all the variables
10.75x^2+20x-751.45=0
a = 10.75; b = 20; c = -751.45;
Δ = b2-4ac
Δ = 202-4·10.75·(-751.45)
Δ = 32712.35
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-\sqrt{32712.35}}{2*10.75}=\frac{-20-\sqrt{32712.35}}{21.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+\sqrt{32712.35}}{2*10.75}=\frac{-20+\sqrt{32712.35}}{21.5} $
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